Questionnaire
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The main reason why theories are created is that they tend to explain a fact or a phenomena using suggested ideas that are based on principles. Landing to the moon is an activity that was practiced and witnessed by human beings. Therefore, no theory is needed whatsoever to explain the event.
The speed to be measured is that of wind. The materials needed are: four cups whose shapes are hemispherical, and a spindle. The cups are attached to the spindle and the spindle vertically mounted on the ground, in such a way that the cups are approximately 10m above the ground. The cups are meant to rotate freely about the spindle and face the same circumferential direction. The rate of rotation of the cups should be directly proportional to the wind velocity. It is then calibrated against a standard anemometer to determine the speed of wind per a given rate of rotation. The anemometer is placed in an open place where it has access to wind from all directions. The number of spins is counted in intervals, for instance, hourly and recorded. The rate of rotation is then converted to wind speed by using the previously acquired calibration.
A stone held by a string spinning about a constantly rotating body. The forces experienced on the stone are: centripetal force balanced by centrifugal force and the force experienced on the string is tensile, due to the centrifugal force. When the rate of body’s rotation increases, the centripetal force increases, and the centrifugal force counteractively increases. The stone’s radial velocity increases and the air resistance increases to keep it at a constant new radial velocity.
Assuming the acceleration due to gravity on Earth is 10m/s2,
We know that:
F=mg
Where F= Force
M= mass
g = acceleration due to gravity
Substituting:
500=10m
∴m=50kg
In Jupiter,
F=50×26
=1300N
=1.3kN
F=mg..(i)
and
v-u=gt
Where v = velocity
t= time taken
∴g=v-ut(ii)
But g=20m/s2 and
u = 0m/s (free fall)
20=vt
∴v=20t
Given
x= 15m
y= 45m
vfy=viy2+2gy
Where viy = vertical initial velocity (0m/s for horizontal launch)
t = time taken
g = acceleration due to gravity (9.8m/s2)
vfy = vertical final velocity
vfy=2×9.8×45
vfy=29.70m/s
And we know that
vfy=viy+gt
29.70=gt
t=3.03s
But we know that
x=vixt
15=vix×3.03
∴ vix=4.95m/s
The horizontal speed is achievable hence they can succeed jumping into the pool.
Given
Vb =600miles/hour
Va = 600 miles/hour
When bullet fired eastwards, net speed:
va+b = 600+600=1200 miles/hour. It is possible to measure.
When the bullet travels in the opposite direction (westwards),
va+b= 600+(-600)=0m/s. The bullet drops downwards.
It is a projectile. The horizontal component of the projectile is the airplane’s (600 miles/hour eastwards)
Given
md=50kg
ap=-6.2m/s
therefore,
R=mdap
=50×-6.2
=-310N drag force
The assumption is that the time taken for the truck to tow the boat and trailer to achieve the velocities stated as shown. The higher the mass of the trailer and boat, the higher the force of truck on them. The higher the mass of the truck, the higher the force of trailer and boat on the truck. Therefore, scenario C meets the condition that the force of truck on trailer being greater than the force of trailer on the truck.
True
True
False
True
False
Since force=mass x acceleration, Betty accelerates faster than Bianca hence Betty uses more force than Bianca. Since work is quantified as force x distance, and distance is constant, Betty does more work than Bianca since Betty used more force. In terms of power, power is work/time or force x velocity. Therefore, Betty uses more power since she used more force and acquired higher velocity that Bianca.
Given:
Circumference = 2m,
Speed of wheel = 1rev/sec
Distance covered in 1 revolution
=2m
Since speed of wheel = 1 rev/sec,
Linear speed of bicycle
=2m×1 rev/second
=2m/s
The force of gravity induces a fall on the woman and she experiences a vertical circular motion due to centripetal acceleration induced by the swinging action of the hangers. When the girl undergoes the upward motion phase, the centripetal acceleration reduces and after releasing herself, the inertia in her body projects her tangentially, leading her to the direction of the man, who gets hold of her before force of gravity pulls her to the ground.
We know that
F=Gm1m2d2
Where F= gravitational force between the two bodies
G = Universal Constant
m1 and m2 = masses of the bodies
F2-F1F1=116=G(m1m2d1-(m1m2)d2)Gd2(m1m2)
116=1d1-1d2×d2
6400×1716=d2
=6800m
Move 400 m above the earth’s surface.
We know that
F=Gm1m2d2
Since the sun’s mass is greater than that of the moon’s mass, and the distance between the sun and the moon is 400 times farther than earth than the moon, d between the sun and the moon is less and since mass of the moon is less than that of Earth, gravitational pull of the moon and the sun is less than that of the sun and Earth.
U=Gm1m2r=7000 MJ
And
KE=12FR=Gm1m22r=4000 MJ
Therefore, total energy, E
=U+KE=11000 MJ
At another point,
U=2000MJ
KE=E-U
=11000-2000
KE=9000MJ
m1v1+m2v2=(m1+m2)v
0+10m1=3m1v
v=3.33m/s
Force = rate of change in momentum
F=m(v-u)t=ma
But
v2=u2+2as
0=3002+2a×0.05
a=-900×103m/s
∴F=0.002×900×103
=-1800N
According the theory of relativity, the higher the speed of travel, the slower the time moves. Therefore, a normal time taken for a traveler on speed of light is the same as a longer period of time for a person moving in a lesser speed. Hence one grows older slowly.
A light beam has light particles in form of photons which are almost weightless, hence behave more like a wave than a particle, hence it cannot be affected by gravity. A baseball has more weight which makes it behave more of a particle than a wave, which makes it attracted by gravity.
REFERENCES
Basu, U., & Mandal, B. N. (2008). Applied mathematics. New Delhi: Narosa Pub. House, pg. 45-59.
Coletta, V. P., & Physics Curriculum & Instruction, Inc. (2010). Physics fundamentals. Lakeville, MN: Physics Curriculum & Instruction, pg. 94-116.
