3. What is the volts/div setting and the time/div setting after using auto scale?
Answer: Volt/div setting= 1V, time/div= 2 µs
5. What is the new time/div setting?
Answer= 1,340µs
Answer: Vpp = 4.71V Vp= 2.25 V, Frequency= 1/T =1/1340 = 0.75 kHz
7. t= 740 µs, Freq= 1/T =(1/740 µs) = 1.6 kHz
8. Vp=4.761V
Calculations
Percentage diff for Vpp (V) = (Vpp2-Vpp1)/Vpp1 = (4.76-4.71)/4.76 = (0.05/4.76) x 100 = 1.05%
Percentage diff for time (µs) = (t1-t2)/t2 = (1340 – 740)/740 = (600/1340) x 100 = 44.78%
Percentage diff for frequency (kHz) = (f2-f1)/f1 = (1.6 – 0.75)/1.6 = 53%
Questions and Answers
Why is there a percentage difference between the two methods of finding frequency and Vpp?
Answer: This is as a result of the difference in the accuracy of the two methods. The cursors are more accurate than the visual estimates.
What happens to the signal if you make the time/div very small? Very big?
Answer: when the value of the time/div is very small the measured waveform will appear too big and the signal will look like a continuous line. This is because at that point in time the beam sweeps very fast that its motion is invisible to the eye.
Answer: when the value of the time/div is very big the waveform appears too smooth that the shape will not be seen.
