Mathematical computations become very momentous when researchers find definite solutions concerning problems. Otherwise, it will not be prudent if solutions are not found. In that regard, calculating of particular solutions especially on indefinite figures requires integration. Integration is the exact opposite of differentiation method. Ideally, integration will result in finding exact solutions in a particular figurative representation
Taking an example below, double or iterated integrals can be computed with ease. It requires a mathematician to follow concise rules of integration and by so doing substituting the right figures to determine the exact answer. In our case study, the following figure can be used for illustration purposes to demonstrate how iterated integration can best be carried out.
The exact values that define the region lies in the range of 0≤x≤2 and 0≤y≤1 as shown above. The values of y range from 0-1 while those of x ranges from 0-2. Now to find the exact area defined by the region enclosed above, call it region R, iterated integration is a requirement. From computation, A=02xy2dA. However, first we iterate, for x and then y with respect to the exact values.
A=02x2/2dy= {x22y2} dy =2y2dy, now another task is integrating 2y2 and evaluate it from 0-1, so that A1= {012y2dy}= {23y3} and evaluate it by substitution, thus, 23*13-23*03= 2/3
Conclusively, since the exact area is needed, the values of zero in the above illustration will not alter the computation since they will not affect the result. However, iterated integration infers to the fact that one of the variables is integrated while the other is kept constant. For instance, in the above calculations, while x was integrated, the values of y remained constant. Moreover, when integrating y- so do the values of x remain constant as well. The final answer in the illustration above is 2/3
Good Essay On Weekly Journal
Type of paper: Essay
Topic: Evaluation, Integration, Region, Illustration, Range
Pages: 1
Words: 300
Published: 03/15/2020
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