Essays on Damping

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Abstract

Further experiment is devoted to an adjustable air damper coefficient measurement. To calculate this coefficient, a flexible air damper is used in the experiment. Three integrative components of the experiments were applied: Lab View, air damper, and the potentiometer. First, test focuses on the equation ratio between the position and the voltage (d = -0.3504 V + 1.8397). Further, the experiment considers velocity measurement with the help of different weights. The main statement of the experiment is that the Damping factor Value is 2.8111lb*s Incp. Based on this value, further experiment is conducted. This value means a constant nature of ...

Introduction

This experiment aims to examine the transient phase of a second order circuit. By definition, a second order circuit consists of circuit elements which are a resistor, an inductor and a capacitor connected either in series or parallel. The transient phase of the second order circuit used in this experiment was investigated by measuring the voltage across the capacitor and the resistor. The measured voltage will help determine whether the transient phase is; overdamped, critically damped or under-damped.

Equipment’s used in the Experiment

An oscilloscope, a function generator, resistors, an inductor and a capacitor. Procedure The voltage v(t) of the circuit 8.2 was ...

Introduction

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PURPOSE

Design an active second order Low-pass filter and characterize its frequency response.EQUIPMENT AND COMPONENTS Oscilloscope Power Supply Function Generator UA741 or LM741 OP AMP 4.7 nF Capacitors

Resistors

PRELAB 1. The RC circuit is shown in the following figure. Node Voltage Analysis is done in order to generate a transfer function Tvs=V2sV1s. In the circuit, voltage at node A is also the input voltage (V1=VA), and voltage at node D is also the output voltage (V2=VD).

KCL at node B:

V1-VBR1=VB-V21/sC1+VB-VCR2 (1)

KCL at node C:

VB-VCR2=VC1/sC2 (2) V2=uVC→VC=V2u (3)

Simplifying (2):

VB=VC1+sR2C2 (4)

Then, substituting (3) to (4):

VB=V2u1+sR2C2 (5)

Substituting (3) and (5) to (1):

V1-V2u1+sR2C2R1=V2u1+sR2C2-V21sC1+V2u1+sR2C2-V2uR2 V1-V2u1+sR2C2R1=V2u1-u+sR2C21sC1+V2usR2C2R2 V1-V2u1+ ...