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Heat and Thermodynamics
Experiment 1: Isobaric (constant pressure) Process P1 = P2 = 100 kPa The blanks have been filled in red.
in by
out on
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in
According to ideal gas law, PV = nRT For a constant mass, isobaric process, V/T = nR/P = constant. Hence, V1/T1 = V2/T2. For each of the cases, V1/T1 = 1/300 dm3/K. V2/T2 has been calculated in the table below for each case.
3.33 x 10-3 3.33 x 10-3
3.33 x 10-3 3.33 x 10-3
3.33 x 10-3 3.33 x 10-3
3.33 x 10-3 3.33 x 10-3
3.33 x ...
Heat and Thermodynamics
Work out the following problems. Be sure to show your work in detail. See the "Module 5 Handout" for examples of how the problems should be solved and presented.
1. How much energy (in J) is required to raise the temperature of 500 g of water from 20 to 100C, and then turn it to steam at 100C? Variables: m = 500g = 0.5 Kg Increase in water temperature, ∆T = 100-20= 800C Latent heat at 1000C, Lv =2260 KJ/Kg Specific heat capacity of water, c = 4.185 kJ/Kg/0C ∆Q = ? Relationships: ∆Q = m(c∆ ...
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